-3c^2(c+11)-(4c-5)(3c-2)=0

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Solution for -3c^2(c+11)-(4c-5)(3c-2)=0 equation: 



-3c^2(c+11)-(4c-5)(3c-2)=0

We multiply parentheses ..

-3c^2(c+11)-(+12c^2-8c-15c+10)=0

We get rid of parentheses

-3c^2(c+11)-12c^2+8c+15c-10=0

We add all the numbers together, and all the variables

-12c^2-3c^2(c+11)+23c-10=0

We move all terms containing c to the left, all other terms to the right

-12c^2-3c^2(c+11)+23c=10

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